Someone's signature was a challenge about an integral...
Integral of e^x , I think

The solution is simple,

(e^x) / Log(e) + C

or simply

e^x + C

I don't remember who was he, but the answer is here
Bye

Isn't the integral of e^x just e^x ? (plus some arbitrary constant)
I think the challenge in the signature was to take the integral of e^x², but I may be mistaken as I haven't seen that sig in a while

jeah, because e is chosen in that way that log(e) = 1, so you can leave away log(e), but you dont have to.

I think it was lefeu...